I have this line of code for page load:
if ($("input").is(':checked')) {
and it works fine when the radio button input is checked. However, I want the opposite. Something along the lines of
if ($("input").not(.is(':checked'))) {
so that my if statement runs when none of the radiobuttons are selected. What is the best way to go about this?
From stackoverflow
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if ( ! $("input").is(':checked') )
Doesn't work?
You might also try iterating over the elements like so:
var iz_checked = true; $('input').each(function(){ iz_checked = iz_checked && $(this).is(':checked'); }); if ( ! iz_checked )
Nathan Long : You might also filter that list by the name attribute this group of radio buttons share. -
if ($("input").is(":not(:checked)"))
AFAIK, this should work, tested against the latest stable jQuery (1.2.6).
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If my firebug profiler work fine (and i know how to use it well), this:
$('#communitymode').attr('checked')
is faster than
$('#communitymode').is('checked')
You can try on this page :)
And then you can use it like
if($('#communitymode').attr('checked')===true) { // do something }
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$("input").is(":not(':checked')"))
This is jquery 1.3, mind the ' and " signs!
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$('input:radio[checked=false]');
this will also work
input:radio:not(:checked)
or
:radio:not(:checked)
Antwan : This will work for sure. Took me a while to figure out. It's the most elegant you can get without writing any code.
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